document.write( "Question 164506: 1)Samantha is 8 and two-third years older than Jason.The sum of their age is 23 years.How old are Samantha and Jason?
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Algebra.Com's Answer #121234 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! 1)Samantha is 8 and two-third years older than Jason. \n" ); document.write( "The sum of their age is 23 years. \n" ); document.write( "How old are Samantha and Jason? \n" ); document.write( ": \n" ); document.write( "Let s = Samantha's age now \n" ); document.write( "Let j = Jason's age now \n" ); document.write( ": \n" ); document.write( "Write an equation for each statement: \n" ); document.write( ": \n" ); document.write( "\"Samantha is 8 and two-third years older than Jason.\" \n" ); document.write( "s = j + 8 \n" ); document.write( "Convert to an improper fraction \n" ); document.write( "s = j + \n" ); document.write( "get rid of the denominator, multiply equation by 3 \n" ); document.write( "3s = 3j + 26 \n" ); document.write( ": \n" ); document.write( "\"The sum of their age is 23 years\" \n" ); document.write( "s + j = 23 \n" ); document.write( "s = 23 - j \n" ); document.write( ": \n" ); document.write( ".How old are Samantha and Jason? \n" ); document.write( ": \n" ); document.write( "Substitute (23-j) for s in the equation: 3s = 3j + 26 \n" ); document.write( "3(23-j) = 3j + 26 \n" ); document.write( ": \n" ); document.write( "69 - 3j = 3j + 26 \n" ); document.write( ": \n" ); document.write( "69 - 26 = 3j + 3j \n" ); document.write( "; \n" ); document.write( "43 = 6j \n" ); document.write( "j = \n" ); document.write( "j = 7 \n" ); document.write( "then \n" ); document.write( "s = 23 - 7 \n" ); document.write( "s = 15 \n" ); document.write( "; \n" ); document.write( ": \n" ); document.write( "We can check that in the 1st statement \n" ); document.write( "s = j + 8 \n" ); document.write( "15 |