document.write( "Question 164494: Kris drove part of a 185 mile trip at 50 mph and the rest at 55 mph. Find the distance she traveled at 50 mph if her total driving time was 3 hours and 30 minutes. \n" ); document.write( "
Algebra.Com's Answer #121222 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Kris drove part of a 185 mile trip at 50 mph and the rest at 55 mph. Find the distance she traveled at 50 mph if her total driving time was 3 hours and 30 minutes. \n" ); document.write( ": \n" ); document.write( "Let d = distance traveled at 50 mph \n" ); document.write( "Then the rest would be: \n" ); document.write( "(185-d) = distance traveled at 55 mph \n" ); document.write( ": \n" ); document.write( "Change 3 hr 30 min to 3.5 hrs \n" ); document.write( ": \n" ); document.write( "Write a time equation: Time = \n" ); document.write( ": \n" ); document.write( "Time at 50 mph + time at 55 mph = 3.5 hrs \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( "Multiply equation by a common denominator 50*55 = 2750 \n" ); document.write( "2750* \n" ); document.write( "Cancel the denominators, results \n" ); document.write( "55d + 50(185-d) = 9625 \n" ); document.write( ": \n" ); document.write( "55d + 9250 - 50d = 9625 \n" ); document.write( "; \n" ); document.write( "55d - 50d = 9625 - 9250 \n" ); document.write( ": \n" ); document.write( "5d = 375 \n" ); document.write( "d = \n" ); document.write( "d = 75 mi at 50 mph \n" ); document.write( "; \n" ); document.write( ": \n" ); document.write( "Check solution by finding the time at each speed \n" ); document.write( "(185-75)/55 = 2hr \n" ); document.write( " 75/50 = 1.5 hrs; adds up to 3.5 hrs \n" ); document.write( " |