document.write( "Question 164494: Kris drove part of a 185 mile trip at 50 mph and the rest at 55 mph. Find the distance she traveled at 50 mph if her total driving time was 3 hours and 30 minutes. \n" ); document.write( "
Algebra.Com's Answer #121222 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
Kris drove part of a 185 mile trip at 50 mph and the rest at 55 mph. Find the distance she traveled at 50 mph if her total driving time was 3 hours and 30 minutes.
\n" ); document.write( ":
\n" ); document.write( "Let d = distance traveled at 50 mph
\n" ); document.write( "Then the rest would be:
\n" ); document.write( "(185-d) = distance traveled at 55 mph
\n" ); document.write( ":
\n" ); document.write( "Change 3 hr 30 min to 3.5 hrs
\n" ); document.write( ":
\n" ); document.write( "Write a time equation: Time = \"dist%2Fspeed\"
\n" ); document.write( ":
\n" ); document.write( "Time at 50 mph + time at 55 mph = 3.5 hrs
\n" ); document.write( "\"d%2F50\" + \"%28%28185-d%29%29%2F55\" = 3.5
\n" ); document.write( ":
\n" ); document.write( "Multiply equation by a common denominator 50*55 = 2750
\n" ); document.write( "2750*\"d%2F50\" + 2750*\"%28%28185-d%29%29%2F55\" = 2750(3.5)
\n" ); document.write( "Cancel the denominators, results
\n" ); document.write( "55d + 50(185-d) = 9625
\n" ); document.write( ":
\n" ); document.write( "55d + 9250 - 50d = 9625
\n" ); document.write( ";
\n" ); document.write( "55d - 50d = 9625 - 9250
\n" ); document.write( ":
\n" ); document.write( "5d = 375
\n" ); document.write( "d = \"375%2F5\"
\n" ); document.write( "d = 75 mi at 50 mph
\n" ); document.write( ";
\n" ); document.write( ":
\n" ); document.write( "Check solution by finding the time at each speed
\n" ); document.write( "(185-75)/55 = 2hr
\n" ); document.write( " 75/50 = 1.5 hrs; adds up to 3.5 hrs
\n" ); document.write( "
\n" );