document.write( "Question 164518: Please help me solve this Word problem:
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Algebra.Com's Answer #121218 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
Let x=length and y=width\r
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\n" ); document.write( "\n" ); document.write( "Perimeter: \"P=2x%2B2y\" where x and y are the length and width (the order doesn't matter)\r
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\n" ); document.write( "\n" ); document.write( "Since the \"length of a rectangle is 3cm greater than its width\" this means that \"x=y%2B3\"\r
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\n" ); document.write( "\n" ); document.write( "\"P=2x%2B2y\" Start with the given perimeter formula\r
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\n" ); document.write( "\n" ); document.write( "\"26=2%28y%2B3%29%2B2y\" Plug in \"P=26\" and \"x=y%2B3\" \r
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\n" ); document.write( "\n" ); document.write( "\"26=2y%2B6%2B2y\" Distribute\r
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\n" ); document.write( "\n" ); document.write( "\"26-6=2y%2B2y\" Subtract 6 from both sides\r
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\n" ); document.write( "\n" ); document.write( "\"20=4y\" Combine like terms\r
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\n" ); document.write( "\n" ); document.write( "\"20%2F4=y\" Divide both sides by 4 to isolate y\r
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\n" ); document.write( "\n" ); document.write( "\"y=5\" Reduce and rearrange the equation\r
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\n" ); document.write( "\n" ); document.write( "\"x=y%2B3\" Go back to the second equation\r
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\n" ); document.write( "\n" ); document.write( "\"x=5%2B3\" Plug in \"y=5\"\r
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\n" ); document.write( "\n" ); document.write( "\"x=8\" Add\r
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\n" ); document.write( "\n" ); document.write( "So the solutions are \"x=8\" and \"y=5\" which means that the length is 8 cm and the width is cm.
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