document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=164484>Question 164484</A>: <I><SPAN STYLE=\"word-break: break-all;\">  A Chemist has a solution that is 20 % acid and 80 % water. He adds 5 liters of water to make a solution that is 15 % acid. What is the volume of the original solution.\r<BR>\n" );
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document.write( "answer:The original <BR>\n" );
document.write( "solution had 15 liters of water \r<BR>\n" );
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document.write( "need a break down of how my text book got: the original solution had 15 liters of water  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #121195 by </B><A HREF=/tutors/aboutme.mpl?userid=ptaylor><B>ptaylor(2198)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ptaylor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ptaylor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=121195\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <BR>\n" );
document.write( "Let x=volume of the original solution<BR>\n" );
document.write( "Now we know that the amount of pure acid in the original solution (0.20x) plus the amount of pure acid added (0) has to equal the amount of pure acid in the final solution (0.15(5+x)).  So our equation to solve is:\r<BR>\n" );
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document.write( "0.20x=0.15(5+x)  get rid of parens (distributive law)<BR>\n" );
document.write( "0.20x=0.75+0.15x  subtract 0.15x from each side<BR>\n" );
document.write( "0.20x-0.15x==0.75+0.15x-0.15x<BR>\n" );
document.write( "0.05x=0.75  divide each side by 0.05<BR>\n" );
document.write( "x=15 liters-----------------------------------volume of original solution<BR>\n" );
document.write( "CK<BR>\n" );
document.write( "0.20*15=0.15*20<BR>\n" );
document.write( "3=3\r<BR>\n" );
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document.write( "Hope this helps---ptaylor<BR>\n" );
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