document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=164480>Question 164480</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Fifty gallons of a 90% alcohol solution is obtained by mixing a 100% solution with a 75% solution.  How many gallons of each solution must be used to obtain the desired mixture? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #121193 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=121193\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> X+.75(5-X)=.9*5<BR>\n" );
document.write( "X+3.75-.75X=4.5<BR>\n" );
document.write( ".25X=4.5-3.75<BR>\n" );
document.write( ".25X=.75<BR>\n" );
document.write( "X=.75/.25<BR>\n" );
document.write( "X=3 GALLONS OD 100% SOLUTION.<BR>\n" );
document.write( "PROOF:<BR>\n" );
document.write( "3+.75(5-3)=.9*5<BR>\n" );
document.write( "3+.75*2=4.5<BR>\n" );
document.write( "3+1.5=4.5<BR>\n" );
document.write( "4.5=4.5 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );