document.write( "Question 164477: A bicycle trip of 120 miles would have taken 3 hours less if the average speed had been increased by 2 miles per hour. Find the average speed of the bicycle. \n" ); document.write( "
Algebra.Com's Answer #121192 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! 120/X=[120/(X+2)]+3 \n" ); document.write( "X[120/(X+2)+3=120 \n" ); document.write( "120X/(X+2)+3X=120 \n" ); document.write( "[(120X+3X(X+2)]/(X+2)=120 \n" ); document.write( "(120X+3X^2+6X)/(X+2)=120 \n" ); document.write( "126X+3X^2=120(X+2) \n" ); document.write( "3X^2+126X=120X+240 \n" ); document.write( "3X^2+126X-120X-240=0 \n" ); document.write( "3X^2+6X-240=0 \n" ); document.write( "3(X^2+2X-80)=0 \n" ); document.write( "3(X+10)(X-8)=0 \n" ); document.write( "X-8=0 \n" ); document.write( "X=8 MPH IS THE SLOWER TRIP. \n" ); document.write( "8+2=10 MPH FOR THE FASTER TRIP. \n" ); document.write( "120/8=15 HOURS. \n" ); document.write( "120/10=12 HOURS. \n" ); document.write( "240/X=27 \n" ); document.write( "27X=240 \n" ); document.write( "X=240/27 \n" ); document.write( "X=8.89 MPH IS THE AVERAGE SPEED.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |