document.write( "Question 164453: 2. An express and local train leave Gray’s Lake at 3 P.M. and head for Chicago 50 miles away. The express travels twice as fast as the local, and arrives 1 hour ahead of it. Find the speed of each train. \r
\n" );
document.write( "\n" );
document.write( " \n" );
document.write( "
Algebra.Com's Answer #121179 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! An express and local train leave Gray’s Lake at 3 P.M. and head for Chicago 50 \n" ); document.write( " miles away. The express travels twice as fast as the local, and arrives 1 hour \n" ); document.write( " ahead of it. Find the speed of each train. \n" ); document.write( ": \n" ); document.write( "Let s = local train speed \n" ); document.write( "then \n" ); document.write( "2s = express train speed \n" ); document.write( ": \n" ); document.write( "Write a time equation: Time = \n" ); document.write( ": \n" ); document.write( "Freight time = Express time + 1 hr \n" ); document.write( " \n" ); document.write( "Multiply equation by 2s to get rid of the denominators \n" ); document.write( "2(50) = 50 + 2s \n" ); document.write( "100 - 50 = 2s \n" ); document.write( ": \n" ); document.write( "s = \n" ); document.write( "s = 25 mph is the freight speed, obviously 50 mph is the express speed \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check solution by find the time of each \n" ); document.write( "50/25 = 2 hr \n" ); document.write( "50/50 = 1 hr, (1 hr less than the freight \n" ); document.write( " |