document.write( "Question 164453: 2. An express and local train leave Gray’s Lake at 3 P.M. and head for Chicago 50 miles away. The express travels twice as fast as the local, and arrives 1 hour ahead of it. Find the speed of each train. \r
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Algebra.Com's Answer #121179 by ankor@dixie-net.com(22740)\"\" \"About 
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An express and local train leave Gray’s Lake at 3 P.M. and head for Chicago 50
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\n" ); document.write( "Let s = local train speed
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\n" ); document.write( "2s = express train speed
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\n" ); document.write( "Write a time equation: Time = \"dist%2Fspeed\"
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\n" ); document.write( "Freight time = Express time + 1 hr
\n" ); document.write( "\"50%2Fs\" = \"50%2F%282s%29\" + 1
\n" ); document.write( "Multiply equation by 2s to get rid of the denominators
\n" ); document.write( "2(50) = 50 + 2s
\n" ); document.write( "100 - 50 = 2s
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\n" ); document.write( "s = \"50%2F2\"
\n" ); document.write( "s = 25 mph is the freight speed, obviously 50 mph is the express speed
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\n" ); document.write( "Check solution by find the time of each
\n" ); document.write( "50/25 = 2 hr
\n" ); document.write( "50/50 = 1 hr, (1 hr less than the freight
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