document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=164323>Question 164323</A>: <I><SPAN STYLE=\"word-break: break-all;\"> at the deli, a sub sandwich with 8 ouces of meat costs 5.35. extra meat is availible for .30 per ounce. if scott bought a sub for 6.55, how much extra meat,m, did he order? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #121170 by </B><A HREF=/tutors/aboutme.mpl?userid=ptaylor><B>ptaylor(2198)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ptaylor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ptaylor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=121170\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let m=amount of extra meat<BR>\n" );
document.write( "Cost of the extra meat=0.30m\r<BR>\n" );
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document.write( "Now we are told that the cost of the basic sub(5.35) plus the cost of the extra meat(0.30m) equals 6.55.  So, our equation to solve is:\r<BR>\n" );
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document.write( "5.35+0.30m=6.55  subtract 5.35 from both sides<BR>\n" );
document.write( "5.35-5.35+0.30m=6.55-5.35  collect like terms\r<BR>\n" );
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document.write( "0.30m=1.20  divide each side by .30<BR>\n" );
document.write( "m=4 ounces---------------amount of extra meat that he ordered\r<BR>\n" );
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document.write( "CK<BR>\n" );
document.write( "5.35+4*0.30=6.55<BR>\n" );
document.write( "5.35+1.20=6.55<BR>\n" );
document.write( "6.55=6.55\r<BR>\n" );
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document.write( "Hope this helps---ptaylor </SPAN>\n" );
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