document.write( "Question 164386: I need help with this question as soon as possible. I have been working on it and cannot figure it out.\r
\n" ); document.write( "\n" ); document.write( "The weight of an object follows this equation: \"w=Cr%5E-2\" where C is the constant, r is the distance from the center of the earth (3963 miles). Using the value of C = 1570536900, determine how much an object would weigh in Death Valley (282 feet below sea level).\r
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Algebra.Com's Answer #121106 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
The weight of an object follows this equation: \"w=Cr%5E-2\" where C is the constant, r is the distance from the center of the earth (3963 miles). Using the value of C = 1570536900, determine how much an object would weigh in Death Valley (282 feet below sea level).
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\n" ); document.write( "since we have the radius in miles we have to convert 282 ft to mile:\r
\n" ); document.write( "\n" ); document.write( "\"282%2F5280\" = .05341 mi below sea level:\r
\n" ); document.write( "\n" ); document.write( "\"w=Cr%5E-2\"
\n" ); document.write( "the reciprocal of r will take care of the neg exponent
\n" ); document.write( "\"w=C%2Fr%5E2\"
\n" ); document.write( "Substitute for C and r, subtract the dist below sealevel
\n" ); document.write( "\"w=1570536900%2F%28%283963-.05341%29%5E2%29\"
\n" ); document.write( "\"w=1570536900%2F%28%283962.94659%29%5E2%29\"
\n" ); document.write( "\"w=1570536900%2F15704940.21\"
\n" ); document.write( "w = 100.00273 lb; Means 100 lb weight in death valley is slightly heavier
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\n" ); document.write( "A lot numbers to crunch here. Check my math on your calc.
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