document.write( "Question 164371This question is from textbook Heart of Mathmatics
\n" ); document.write( ": Suppose you know the base of a rectangle has a length of 4 inches and a diagonal has a length of 5 inches. Find the area of the rectangle? \r
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\n" ); document.write( "\n" ); document.write( "I'm clueless on this one. I just cant seem to get this. Any help would be greatly appreciated.
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Algebra.Com's Answer #121102 by nerdybill(7384)\"\" \"About 
You can put this solution on YOUR website!
Because the \"diagonal\", \"base\" and \"height\" of the rectangle forms a \"right triangle\" we can apply Pythagorean's theorem.
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\n" ); document.write( "Let h = height
\n" ); document.write( "then
\n" ); document.write( "h^2 + 4^2 = 5^2
\n" ); document.write( "h^2 + 16 = 25
\n" ); document.write( "h^2 = 9
\n" ); document.write( "h = 3 inches
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\n" ); document.write( "Area is then:
\n" ); document.write( "\"height\" * \"base\"
\n" ); document.write( "= 3 * 4 = 12 square inches\r
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