document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=164341>Question 164341</A>: <I><SPAN STYLE=\"word-break: break-all;\">    A SIX LITER MIXTURE OF ALCOHOL AND WATER IS 75% ALCOHOL.HOW MUCH ALCOHOL MUST BE ADDED TO THE EXISTING MIXTURE TO PRODUCE A MIXTURE THAT IS 80% ALCOHOL?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #121085 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=121085\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 6*.75+x=.80(6+x)<BR>\n" );
document.write( "4.5+x=4.8+.8x<BR>\n" );
document.write( "x-.8x=4.8-4.5<BR>\n" );
document.write( ".2x=.3<BR>\n" );
document.write( "x=.3/.2<BR>\n" );
document.write( "x=1.5 liters of pure alcohol is needed.<BR>\n" );
document.write( "Proof:<BR>\n" );
document.write( "6*.75+1.5=.8(6+1.50<BR>\n" );
document.write( "4.5+1.5=.8*7.5<BR>\n" );
document.write( "6=6 </SPAN>\n" );
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