document.write( "Question 164348This question is from textbook Algebra and Trigonometry
\n" ); document.write( ": Please help me solve this problem. I do not understanding the problem at all.\r
\n" ); document.write( "\n" ); document.write( " A forester mixes gasoline and oil to make 2 gallons of mixture for his two-cycle chain-saw engine. This mixture is 32 parts gasoline and 1 part two-cycle oil. How much gasoline must be added to bring the mixture to 40 parts gasoline and 1 part oil?
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Algebra.Com's Answer #121078 by ankor@dixie-net.com(22740)\"\" \"About 
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A forester mixes gasoline and oil to make 2 gallons of mixture for his two-cycle chain-saw engine. This mixture is 32 parts gasoline and 1 part two-cycle oil. How much gasoline must be added to bring the mixture to 40 parts gasoline and 1 part oil?
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\n" ); document.write( "Convert the mixtures to percent oil (decimal equiv):
\n" ); document.write( "\"1%2F%28%2832%2B1%29%29\" = .0303
\n" ); document.write( "\"1%2F%28%2840%2B1%29%29\" = .0244
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\n" ); document.write( "Let x = amt of gas added to make the 40:1 mixture
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\n" ); document.write( "Write an amt of oil equation, (amt of oil remains the same, only the % changes)
\n" ); document.write( ".0303(2) = .0244(2+x)
\n" ); document.write( ".0606 = .0488 + .0244x
\n" ); document.write( ".0606 - .0488 = .0244x
\n" ); document.write( ".0118 = .0244x
\n" ); document.write( "x = \".0118%2F.0244\"
\n" ); document.write( "x = .4836 gal of gas to be added
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