document.write( "Question 164348This question is from textbook Algebra and Trigonometry
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document.write( ": Please help me solve this problem. I do not understanding the problem at all.\r
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document.write( " A forester mixes gasoline and oil to make 2 gallons of mixture for his two-cycle chain-saw engine. This mixture is 32 parts gasoline and 1 part two-cycle oil. How much gasoline must be added to bring the mixture to 40 parts gasoline and 1 part oil? \n" );
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Algebra.Com's Answer #121078 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! A forester mixes gasoline and oil to make 2 gallons of mixture for his two-cycle chain-saw engine. This mixture is 32 parts gasoline and 1 part two-cycle oil. How much gasoline must be added to bring the mixture to 40 parts gasoline and 1 part oil? \n" ); document.write( ": \n" ); document.write( "Convert the mixtures to percent oil (decimal equiv): \n" ); document.write( " \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( "Let x = amt of gas added to make the 40:1 mixture \n" ); document.write( ": \n" ); document.write( "Write an amt of oil equation, (amt of oil remains the same, only the % changes) \n" ); document.write( ".0303(2) = .0244(2+x) \n" ); document.write( ".0606 = .0488 + .0244x \n" ); document.write( ".0606 - .0488 = .0244x \n" ); document.write( ".0118 = .0244x \n" ); document.write( "x = \n" ); document.write( "x = .4836 gal of gas to be added \n" ); document.write( " |