document.write( "Question 164196: Solve system by the substitution method and indicate wheter each system is independent, inconsistent or dependent
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document.write( "x=1/8y-1
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document.write( "y=1/4x+39\r
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document.write( "Any help is appreciated. \n" );
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Algebra.Com's Answer #121068 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Assume the problem is: \n" ); document.write( "x = \n" ); document.write( "y = \n" ); document.write( "; \n" ); document.write( "Get rid of the denominators, multiply the 1st equation by 8, 2nd equation by 4 \n" ); document.write( "8x = y - 8 \n" ); document.write( "4y = x + 156 \n" ); document.write( ": \n" ); document.write( "Rearrange the 1st equation for substitution \n" ); document.write( "y = (8x + 8) \n" ); document.write( ": \n" ); document.write( "Substitute (8x+8) for y in the 2nd equation \n" ); document.write( "4(8x+8) = x + 156 \n" ); document.write( ": \n" ); document.write( "32x + 32 = x + 156 \n" ); document.write( ": \n" ); document.write( "32x - x = 156 - 32 \n" ); document.write( "; \n" ); document.write( "31x = 124 \n" ); document.write( "x = \n" ); document.write( "x = 4 \n" ); document.write( ": \n" ); document.write( "Find y using eq: y = \n" ); document.write( "y = \n" ); document.write( "y = 1 + 39 \n" ); document.write( "y = 40 \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check solutions in the 1st equation: x = \n" ); document.write( "4 = \n" ); document.write( "4 = 5 - 1 \n" ); document.write( " |