document.write( "Question 164281: Determine the linear function whose graph is a line that contain the pionts (-3,-1) and (2, -6) \n" ); document.write( "
Algebra.Com's Answer #121057 by algebrapro18(249)\"\" \"About 
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Determine the linear function whose graph is a line that contain the pionts (-3,-1) and (2, -6)\r
\n" ); document.write( "\n" ); document.write( "first we want to find the slope of this line\r
\n" ); document.write( "\n" ); document.write( "m = (y2-y1)/(x2-x1) = (-6--1)/(2--3) = (-6+1)/(2+3) = -5/5 = -1\r
\n" ); document.write( "\n" ); document.write( "now there are two ways we can do this:\r
\n" ); document.write( "\n" ); document.write( "1) plug things into y = mx + b and solve for b and then get into y = mx + b or standard form.\r
\n" ); document.write( "\n" ); document.write( "we know that y = mx + b is the slope-intercept form of a line. well we know y, m, and x so now we can solve the slope-intercept form for b.\r
\n" ); document.write( "\n" ); document.write( "y = mx + b let y = -6 and x = 2
\n" ); document.write( "-6 = -1(2) + b
\n" ); document.write( "-6 = -2 + b
\n" ); document.write( "-4 = b\r
\n" ); document.write( "\n" ); document.write( "now we know the point slope form of the line: y = -1x-4 or y=-x-4
\n" ); document.write( "if your teacher wants it in standard form we can write it that way by adding x to both sides you will get x + y = -4. \r
\n" ); document.write( "\n" ); document.write( "2) use the point slope formula\r
\n" ); document.write( "\n" ); document.write( "y-y1 = m(x-x1) where x1 and y1 are points and m is the slope
\n" ); document.write( "y --6 = -1(x-2)
\n" ); document.write( "y +6 = -1(x-2)
\n" ); document.write( "y +6 = -1x +2
\n" ); document.write( "y = -1x + 2 - 6
\n" ); document.write( "y = -1x -4
\n" ); document.write( "y = -x -4\r
\n" ); document.write( "\n" ); document.write( "or in standard form you get x+y = -4\r
\n" ); document.write( "\n" ); document.write( "either way you get the same answer. \r
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