document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=164311>Question 164311</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/061849281x/algebrahomeworkh></A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> The width of a rectangle is 22 centimeters shorter that its length. The perimiter of the rectangular is 160. find its length. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #121054 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=121054\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  The width of a rectangle is 22 centimeters shorter that its length. The perimiter of the rectangular is 160. find its length.<BR>\n" );
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document.write( "Perimeter = 2(length + width)<BR>\n" );
document.write( "160 = 2(L + 22)<BR>\n" );
document.write( "80 = L+22<BR>\n" );
document.write( "L = 58 cm.<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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