document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=164304>Question 164304</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A rectangle has a length that is 6ft more than the width.Its perimeter is 100 ft. What is the area? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #121049 by </B><A HREF=/tutors/aboutme.mpl?userid=algebrapro18><B>algebrapro18(249)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=algebrapro18><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=121049\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A rectangle has a length that is 6ft more than the width.Its perimeter is 100 ft. What is the area?\r<BR>\n" );
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document.write( "l = 6+w<BR>\n" );
document.write( "l+w = 100\r<BR>\n" );
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document.write( "now substituting l into the second equation<BR>\n" );
document.write( "l + w = 100<BR>\n" );
document.write( "(6+w) + w = 100<BR>\n" );
document.write( "6 + 2w = 100<BR>\n" );
document.write( "2w = 94<BR>\n" );
document.write( "w = 47\r<BR>\n" );
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document.write( "now substituting back into the first equation<BR>\n" );
document.write( "l = 6 + w<BR>\n" );
document.write( "l = 6 + 47<BR>\n" );
document.write( "l = 53\r<BR>\n" );
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document.write( "so now we know what the length and with are and we can find the Area of a rectangle using the formula A = lw.  I will leave this for you to do. </SPAN>\n" );
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