document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=164241>Question 164241</A>: <I><SPAN STYLE=\"word-break: break-all;\"> simplify:\r<BR>\n" );
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document.write( "3x^3+18x^2-21x<BR>\n" );
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document.write( "x^3+5x^2-14x </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #121012 by </B><A HREF=/tutors/aboutme.mpl?userid=padmameesala><B>padmameesala(42)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=padmameesala><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=121012\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 3x^3+18x^2-21x<BR>\n" );
document.write( "=3x(x^2+6x-7)     taking 3x as greatest common factor (g.c.f)<BR>\n" );
document.write( "=3x(x^2+7x-x-7) the factors of -7 are 7 and -1 such that 7-1=6(coefficient of x)<BR>\n" );
document.write( "=3x[x(x+7)-1(x+7)]  taking x and -1 as g.cf.s from the 1st and last two terms<BR>\n" );
document.write( "=3x(x+7)(x-1)    taking x+7 as the g.c.f\r<BR>\n" );
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document.write( "x^3+5x^2-14x<BR>\n" );
document.write( "=x(x^2+5x-14)<BR>\n" );
document.write( "=x(x^2+7x-2x-14)  the factors of -14 are 7 and -2 which add up and give 5<BR>\n" );
document.write( "=x[x(x+7)-2(x+7)  taking x and -2 as g.cf.s from the 1st and last two terms<BR>\n" );
document.write( "=x(x+7)(x-2)      taking x+7 as the g.c.f\r<BR>\n" );
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