document.write( "Question 164236: aN INVESTMENT OF $1200 EARNS $96 EACH YEAR. At the same rate, how much additional money must be invested to earn $128 each year? \n" ); document.write( "
Algebra.Com's Answer #121008 by aka042(26)\"\" \"About 
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We first must find the implied interest rate of a $1200 investment earning $96 each year. This can be found as \"1200%2Ar+=+96\" => \"r+=+96%2F1200+=+.08\". Therefore we are investing the $1200 at a 8% interest rate.
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\n" ); document.write( "Now we must use our newly found r to solve for a new investment balance. We do this as follows: \"p%2A.08+=+128\" => \"p+=+128%2F.08+=+1600\". Therefore, we would need to invest $1600 to earn $128 each year.
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