document.write( "Question 164201: I am having trouble with these two questions. Can someone please explain.\r
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document.write( "1. Let z = a + bi represent a general complex number. As noted in the lesson, the conjugate of z, abbreviated conj(z) or conj(a + bi) is the complex number a-bi. Also, the modulus of z, modulus(z) is the \"size\" of z, or SQRT(a^2 + b^2). Which of the following is true for all complex numbers? How did you get to that conclusion?
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document.write( "A) All of the following
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document.write( "B) z*conj(z) = [modulus(z)]^2
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document.write( "C) z + conj(z) = 2a
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document.write( "D) z - conj(z) = 2bi
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document.write( "E) None of the above\r
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document.write( "2. Using the definition of “size” of z from problem #1, which of the following is largest? How did you get to that conclusion?
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document.write( "A) 3i
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document.write( "B) -7
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document.write( "C) 4
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document.write( "D) -2i
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document.write( "E) 4 + 4i
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document.write( "F) None of the above
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Algebra.Com's Answer #120992 by oscargut(2103)![]() ![]() You can put this solution on YOUR website! A) All of the following \n" ); document.write( "B) z*conj(z) = [modulus(z)]^2 \n" ); document.write( "C) z + conj(z) = 2a \n" ); document.write( "D) z - conj(z) = 2bi \n" ); document.write( "E) None of the above \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "B) right because (a+bi)(a-bi)=a^2-b^2i^2=a^2+b^2=[modulus(z)]^2 \n" ); document.write( "C) right because (a+bi)+(a-bi)=2a \n" ); document.write( "D) right because (a+bi)-(a-bi)=2bi\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "A) 3i size is sqrt(9)=3 \n" ); document.write( "B) -7 size is sqrt(49)=7 \n" ); document.write( "C) 4 size is sqrt(16)=4 \n" ); document.write( "D) -2i size is sqrt(4)=2 \n" ); document.write( "E) 4 + 4i size is sqrt(16+16)=sqrt(32)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "so the largest is B) \n" ); document.write( " \n" ); document.write( " |