document.write( "Question 164100: An owner of a gourmet food store has two varieties of herbal teas, one that costs $4 per kilogram and another that costs $5 per kilogram. How many kilograms of each type are needed to make 20 kg of a blend worth $4.60 per kilogram? \n" ); document.write( "
Algebra.Com's Answer #120989 by ptaylor(2198)![]() ![]() You can put this solution on YOUR website! Let x=number of kilos needed of the $4 tea \n" ); document.write( "Then 20-x=number of kilos needed of the $5 tea\r \n" ); document.write( "\n" ); document.write( "Now we know that the value of the tea before it's mixed has to equal the value of the tea after it's mixed, ok? \n" ); document.write( "Value of the tea before it's mixed ($ understood)=4x+5(20-x) \n" ); document.write( "Value of the tea after it's mixed=4.60*20=92 \n" ); document.write( "So, our equation to solve is:\r \n" ); document.write( "\n" ); document.write( "4x+5(20-x)=92 get rid of parens (distributive law) \n" ); document.write( "4x+100-5x=92 subtract 100 from each side \n" ); document.write( "4x+100-100-5x=92-100 collect like terms\r \n" ); document.write( "\n" ); document.write( "-x=-8 multiply each side by -1 \n" ); document.write( "x=8 kilos---------------------------------amount of $4 tea needed \n" ); document.write( "20-x=20-8=12 kilos---------------------------amount of $5 tea needed \n" ); document.write( "CK \n" ); document.write( "4*8+5*12=4.60*20 \n" ); document.write( "32+60=92 \n" ); document.write( "92=92\r \n" ); document.write( "\n" ); document.write( "Hope this helps------ptaylor \n" ); document.write( " |