document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=164105>Question 164105</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A chemist has 60 g of a solution that is 70% acid. How much water should be added to make a solution that is 40% acid? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #120988 by </B><A HREF=/tutors/aboutme.mpl?userid=ptaylor><B>ptaylor(2198)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ptaylor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ptaylor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=120988\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x=amount of water needed\r<BR>\n" );
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document.write( "Now we know that the amount of pure acid in the 60g solution (0.70*60) plus the amount of pure acid in the water that's added(0) has to equal the amoount of pure acid in the final solution (0.40(60+x)).  So our equation to solve is:\r<BR>\n" );
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document.write( "0.70*60=0.40(60+x) get rid of parens (distributive law) and simplify<BR>\n" );
document.write( "42=24+0.40x  subtract 24 from each side<BR>\n" );
document.write( "42-24=24-24+0.40x  collect like terms\r<BR>\n" );
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document.write( "18=0.40x  divide each side by 0.40<BR>\n" );
document.write( "x=45g-------------------------------------amount of water needed\r<BR>\n" );
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document.write( "CK<BR>\n" );
document.write( "0.70*60=0.40*105<BR>\n" );
document.write( "42=42\r<BR>\n" );
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document.write( "Hope this helps---ptaylor </SPAN>\n" );
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