document.write( "Question 164191: Suppose you are at the gas station filling your tank with gas. The function C(g) represents the cost C of filling up the gas tank with g gallons. Given the equation: C(g)=3.03(g)\r
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\n" ); document.write( "\n" ); document.write( "Find C(2)
\n" ); document.write( "Find C(9)
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\n" ); document.write( "I have solved as...
\n" ); document.write( "C(2)=3.03(g)
\n" ); document.write( "C*2-3.03*g=0
\n" ); document.write( "is this correct?\r
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\n" ); document.write( "\n" ); document.write( "C(9)...
\n" ); document.write( "C(9)=3.03(g)
\n" ); document.write( "c*9-3.03*g=0
\n" ); document.write( "Is this correct?
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Algebra.Com's Answer #120985 by aka042(26)\"\" \"About 
You can put this solution on YOUR website!
Hi-\r
\n" ); document.write( "\n" ); document.write( "Whenever we are given a function C(g) and g = some number n, this means that we plug the number n wherever g appears in the equation.
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\n" ); document.write( "So for your first problem, find C(2), we simply plug 2 into the C(g) equation whereever g is. Since C(g) = 3.03*g, then C(2) = 3.03*2 = 6.06. So C(2) = 6.06.
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\n" ); document.write( "For the next problem, C(9) we plug 9 into g to get C(9) = 3.03 * 9 = 27.27. So C(9) = 27.27
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\n" ); document.write( "I think you may be confusing C(g) to mean C * g. Note that when we are writing a function C(g), then C(g) is said C OF g, not C times 6. It may be a little confusing, but C is actually the name of the function, not a variable. So you don't multiply C with anything!
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