document.write( "Question 164019: An office supply store sells three models of computer desk: A, B, and C. In January, the store sold a total of 85 computer desks. The number of model B desks was five more than the number of model C desks, and the number of model A desks was four more than twice the number of model C desks. How many of each model did the store sell in January? \n" ); document.write( "
Algebra.Com's Answer #120984 by aka042(26)![]() ![]() ![]() You can put this solution on YOUR website! If A, B, and C are the number of A model, B model, and C model desks respectively, then we know that in Jan, A + B + C = 85. We are told that the number of b desks was five more than the number of C desks, so B = C + 5. Furthermore, the number of A desks was four more than twice the number of C desks, so A = 4 + 2*C. Now we just substitute for A and B in our initial equation: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "In summary, 42 A desks were sold, 24 B desks were sold, and 19 c desks were sold. \n" ); document.write( " |