document.write( "Question 23319: Solve the system with the elimination method.\r
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document.write( "4x-y=11
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document.write( "3x=3-y \n" );
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Algebra.Com's Answer #12098 by rapaljer(4671)![]() ![]() You can put this solution on YOUR website! 4x-y=11 \n" ); document.write( "3x=3-y\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "In the second equation get it into standard form, by adding +y to each side:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "4x-y=11 \n" ); document.write( "3x +y =3\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Now, just add the two equations together:\r \n" ); document.write( "\n" ); document.write( "7x = 14 \n" ); document.write( "x= 2\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Next, substitute x =2 into EITHER equation. The first will do. \n" ); document.write( "4x-y = 11 \n" ); document.write( "4(2)- y = 11 \n" ); document.write( "8-y = 11 \n" ); document.write( "-y = 3 \n" ); document.write( "y = -3\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The point of solution is (2,-3).\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Check by substituting both values into the OTHER equation: \n" ); document.write( "3x= 3-y \n" ); document.write( "3(2) = 3-(-3) \n" ); document.write( "6=6 \n" ); document.write( "It checks!\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "R^2 at SCC \n" ); document.write( " |