document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=164157>Question 164157</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Write the perimeter formula of a rectangle, and then substitute the following conditions into the formula: The perimeter of a rectangluar garden is 100 feet, and the lengh of the garden in 12 feet more than the width. use x to represent the width. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #120945 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=120945\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2L+2W=PERIMETER<BR>\n" );
document.write( "L=X+12<BR>\n" );
document.write( "W=X<BR>\n" );
document.write( "2(X+12)+2X=100<BR>\n" );
document.write( "2X+24+2X=100<BR>\n" );
document.write( "4X=100-24<BR>\n" );
document.write( "4X=76<BR>\n" );
document.write( "X=76/4<BR>\n" );
document.write( "X=19 FT IS THE WIDTH.<BR>\n" );
document.write( "19+12=31 FOR THE LENGTH.<BR>\n" );
document.write( "PROOF:<BR>\n" );
document.write( "2*31+2*19=100<BR>\n" );
document.write( "62+38=100<BR>\n" );
document.write( "100=100<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );