document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=164107>Question 164107</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How many kilograms of pure alcohol must be added to 40 kg of a 70% alcohol solution to produce an 85% alcohol solution? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #120929 by </B><A HREF=/tutors/aboutme.mpl?userid=rcmcc><B>rcmcc(152)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rcmcc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rcmcc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=120929\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> To solve this question you must first find the quantity of liquid that is not alcohol in the first solution.\r<BR>\n" );
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document.write( "Because the 40kg solution is 70% alcohol 30% of the solution is a fixed variable.\r<BR>\n" );
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document.write( "30% of 40kg = 12kg.\r<BR>\n" );
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document.write( "The second solution is 85% alcohol. Because we can not change the fixed variable the 15% of the new solution weighs 12kg\r<BR>\n" );
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document.write( "if 15% of the new solution weigs 12kg then the entire solution weighs 80kg.\r<BR>\n" );
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document.write( "because your original solution weighs 40kg, and your new solution weighs 80kg, you would need 40kg of pure alcohol added to the old solution to increase the concentration from 70% to 85%. </SPAN>\n" );
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