document.write( "Question 164091: Given three consecutive integers. When half the secondinteger is subtracted from twice the first one the result is eleven less than the third one. Find the three integers. \n" ); document.write( "
Algebra.Com's Answer #120927 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! Let x, x+1 & x+2 be the 3 integers. \n" ); document.write( "2x-(x+1)/2=(x+2)-11 \n" ); document.write( "2x-x/2-1/2=x+2-11 \n" ); document.write( "3x/2-x=-9+1/2 \n" ); document.write( "x/2=-17/2 \n" ); document.write( "x=-17 Answer for the smallest integer. \n" ); document.write( "-17+1=-16 for the middle integer. \n" ); document.write( "-17+2=-15 for the larger integer.. \n" ); document.write( "Proof: \n" ); document.write( "2*-17-(-16/2)=-15-11 \n" ); document.write( "-34-(-8)=-26 \n" ); document.write( "-34+6=-26 \n" ); document.write( "-26=-26 \n" ); document.write( " \n" ); document.write( " |