document.write( "Question 164091: Given three consecutive integers. When half the secondinteger is subtracted from twice the first one the result is eleven less than the third one. Find the three integers. \n" ); document.write( "
Algebra.Com's Answer #120927 by checkley77(12844)\"\" \"About 
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Let x, x+1 & x+2 be the 3 integers.
\n" ); document.write( "2x-(x+1)/2=(x+2)-11
\n" ); document.write( "2x-x/2-1/2=x+2-11
\n" ); document.write( "3x/2-x=-9+1/2
\n" ); document.write( "x/2=-17/2
\n" ); document.write( "x=-17 Answer for the smallest integer.
\n" ); document.write( "-17+1=-16 for the middle integer.
\n" ); document.write( "-17+2=-15 for the larger integer..
\n" ); document.write( "Proof:
\n" ); document.write( "2*-17-(-16/2)=-15-11
\n" ); document.write( "-34-(-8)=-26
\n" ); document.write( "-34+6=-26
\n" ); document.write( "-26=-26
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