document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=164124>Question 164124</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How many pounds of candy selling for $2 a pound should be added to three pounds of candy selling for $3.75 a pound to create a blend, which will sell for $2.75 a pound.\r<BR>\n" );
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document.write( "\"C for the unknown candy\"\r<BR>\n" );
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document.write( "3(3.75) + 2.75 = 2C<BR>\n" );
document.write( "11.25 + 2.75 = 2C<BR>\n" );
document.write( "14 = 2C<BR>\n" );
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document.write( "7 = C<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #120919 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=120919\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> \"How many pounds of candy selling for $2 a pound\" __ 2C\r<BR>\n" );
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document.write( "\"should be added to\" __ +\r<BR>\n" );
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document.write( "\"three pounds of candy selling for $3.75 a pound\" __ 3(3.75)\r<BR>\n" );
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document.write( "\"to create a blend, which will sell for $2.75 a pound\" __ =(3+C)(2.75)\r<BR>\n" );
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document.write( "2C+11.25=8.25+2.75C __ 3=.75C __ 4=C </SPAN>\n" );
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