document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=164124>Question 164124</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How many pounds of candy selling for $2 a pound should be added to three pounds of candy selling for $3.75 a pound to create a blend, which will sell for $2.75 a pound.\r<BR>\n" );
document.write( "\n" );
document.write( "Is it right?????<BR>\n" );
document.write( "\"C for the unknown candy\"\r<BR>\n" );
document.write( "\n" );
document.write( "3(3.75) + 2.75 = 2C<BR>\n" );
document.write( "11.25 + 2.75 = 2C<BR>\n" );
document.write( "14 = 2C<BR>\n" );
document.write( "******<BR>\n" );
document.write( "7 = C<BR>\n" );
document.write( "****** </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #120913 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=120913\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2x+3*3.75=(3+x)*2.75<BR>\n" );
document.write( "2x+11.25=8.25+2.75x<BR>\n" );
document.write( "2x-2.75x=8.25-11.25<BR>\n" );
document.write( "-.75x=-3<BR>\n" );
document.write( "x=-3/-.75<BR>\n" );
document.write( "x=4 pounds of the $2 candy is used.<BR>\n" );
document.write( "PROOF\"<BR>\n" );
document.write( "2*4+11.25=8.25+2.75*4<BR>\n" );
document.write( "8+11.25=8.25+11<BR>\n" );
document.write( "19.25=19.25\r<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );