document.write( "Question 164116This question is from textbook
\n" ); document.write( ": Solve the following algebraically. Trial and error is not an appropriate method of solution. \"matrix%282%2C3%2C%22%22%2C+%22%22%2C%22%22%2Cx%5E%283%2F2%29%2C+%22=%22%2C125+%29\" \n" ); document.write( "
Algebra.Com's Answer #120906 by Edwin McCravy(20059)\"\" \"About 
You can put this solution on YOUR website!
\r\n" );
document.write( " \"matrix%282%2C3%2C%22%22%2C+%22%22%2C%22%22%2Cx%5E%283%2F2%29%2C+%22=%22%2C125+%29\"\r\n" );
document.write( "\r\n" );
document.write( "Raise both sides to the power which is the reciprocal\r\n" );
document.write( "of \"3%2F2\" power, which is the \"2%2F3\" power:\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "Multiply the exponents on the left to remove the\r\n" );
document.write( "parentheses:\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "Cancel:\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "The exponent on the left becomes \"1\"\r\n" );
document.write( "\r\n" );
document.write( "\"matrix%282%2C3%2C%22%22%2C%22%22%2C%22%22%2C+x%5E1%2C%22=%22%2C125%5E%282%2F3%29%29\"\r\n" );
document.write( "\r\n" );
document.write( "and we can drop the 1 exponent:\r\n" );
document.write( "\r\n" );
document.write( "\"matrix%282%2C3%2C%22%22%2C%22%22%2C%22%22%2C+x%2C%22=%22%2C125%5E%282%2F3%29%29\"\r\n" );
document.write( "\r\n" );
document.write( "Use this rule for the right side:  \r\n" );
document.write( "\r\n" );
document.write( "\"matrix%282%2C3%2C%22%22%2C%22%22%2C%22%22%2C+x%2C%22=%22%2C%28root%283%2C125%29%29%5E2+++%29\"\r\n" );
document.write( "\r\n" );
document.write( "Since \"125=5%2A5%2A5=5%5E3\", \"root%283%2C125%29=5\", so we have:\r\n" );
document.write( "\r\n" );
document.write( "\"matrix%282%2C3%2C%22%22%2C%22%22%2C%22%22%2C+x%2C%22=%22%2C%285%29%5E2+++%29\"\r\n" );
document.write( "\r\n" );
document.write( "\"matrix%282%2C3%2C%22%22%2C%22%22%2C%22%22%2C+x%2C%22=%22%2C25+++%29\"\r\n" );
document.write( "\r\n" );
document.write( "Edwin
\n" ); document.write( "
\n" );