document.write( "Question 164045: I need to solve this by the addition method.\r
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document.write( "3/7x+5/9y=27\r
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document.write( "1/9x+2/7y=7 \n" );
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Algebra.Com's Answer #120886 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! I need to solve this by the addition method. \n" ); document.write( "3/7x+5/9y=27 \n" ); document.write( "1/9x+2/7y=7 \n" ); document.write( "------------------ \n" ); document.write( "Assuming you mean \n" ); document.write( "(3x/7) + (5y/9) = 27 \n" ); document.write( "(x/9) + (2y/7) = 7 \n" ); document.write( "Multiply thru both by 63 to eliminate fractions. \n" ); document.write( "27x + 35y = 1701 \n" ); document.write( " 7x + 18y = 441 \n" ); document.write( "Some big numbers, but easier to deal with than fractions. \n" ); document.write( "To get the same coefficients for x, multiply the 1st eqn by 7, the 2nd by 27 \n" ); document.write( "189x + 245y = 11907 \n" ); document.write( "189x + 486y = 11907 \n" ); document.write( "-------------- Uhoh \n" ); document.write( "Subtract 2 from 1 \n" ); document.write( "0x - 241y = 0 \n" ); document.write( "y = 0 \n" ); document.write( "x = 63 \n" ); document.write( "It does check, and fits both eqns \n" ); document.write( " \n" ); document.write( " |