document.write( "Question 164049: ticket prices at concert were $10 for adults, $7 for seniors, and $5 for children. there were twice as many children as adults and 3 more seniors than adults. if the total receipts for the concert were $1236, how many children were in attendance? \n" ); document.write( "
Algebra.Com's Answer #120881 by nerdybill(7384)![]() ![]() You can put this solution on YOUR website! Let x = number adult tickets \n" ); document.write( "then \n" ); document.write( "from \"there were twice as many children as adults\" \n" ); document.write( "2x = number of children tickets \n" ); document.write( "and \n" ); document.write( "from \"3 more seniors than adults\" \n" ); document.write( "x+3 = number senior tickets \n" ); document.write( ". \n" ); document.write( "Because we know the \"total receipts for the concert were $1236\" we have: \n" ); document.write( "10x + 7(x+3) + 5(2x) = 1236 \n" ); document.write( "10x + 7x+21 + 10x = 1236 \n" ); document.write( "27x + 21 = 1236 \n" ); document.write( "27x = 1215 \n" ); document.write( "x = 45 (adult tickets) \n" ); document.write( ". \n" ); document.write( "children tickets: \n" ); document.write( "2x = 2(45) = 90 (children tickets) \n" ); document.write( ". \n" ); document.write( "senior tickets: \n" ); document.write( "x+3 = 45+3 = 48 (senior tickets) \n" ); document.write( " |