document.write( "Question 164046: I need to solve this by substitution or addition, whichever one is easier.\r
\n" ); document.write( "\n" ); document.write( "2y-x=3
\n" ); document.write( "x=3y-5
\n" ); document.write( "

Algebra.Com's Answer #120877 by KnightOwlTutor(293)\"\" \"About 
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2y-x=3\r
\n" ); document.write( "\n" ); document.write( "x=3y-5 \r
\n" ); document.write( "\n" ); document.write( "Replace the x in the first equation with 3y-5\r
\n" ); document.write( "\n" ); document.write( "2y-3y+5=3\r
\n" ); document.write( "\n" ); document.write( "Simplify the y term\r
\n" ); document.write( "\n" ); document.write( "-y+5=3
\n" ); document.write( "Subtract 5 from both sides
\n" ); document.write( "-y=-2\r
\n" ); document.write( "\n" ); document.write( "Divide both sides by -1
\n" ); document.write( "y=2\r
\n" ); document.write( "\n" ); document.write( "x=6-5\r
\n" ); document.write( "\n" ); document.write( "x=1\r
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\n" ); document.write( "\n" ); document.write( "2y-x=3\r
\n" ); document.write( "\n" ); document.write( "x=3y-5 \r
\n" ); document.write( "\n" ); document.write( "Let's plug in the calculated x and y values to confirm\r
\n" ); document.write( "\n" ); document.write( "4-1=3
\n" ); document.write( "1=6-5\r
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