document.write( "Question 164033: The first four terms of a pattern are shown below: \r
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document.write( "ABBA
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document.write( "AABBBAA
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document.write( "AAABBBBAAA
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document.write( "AAAABBBBBAAAA \r
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document.write( "Suppose that this pattern continues, with the As and Bs increasing as shown. \r
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document.write( "Find an expression for the number of Bs in the nth term of the pattern.\r
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document.write( "Use your expression to determine which term has exactly 35% Bs.
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Algebra.Com's Answer #120876 by alicealc(293)![]() ![]() ![]() You can put this solution on YOUR website! the 1st term has 2 Bs and 2 As \n" ); document.write( "the 2nd term has 3 Bs and 4 As \n" ); document.write( "the 3rd term has 4 Bs and 6 As \n" ); document.write( "the 4th term has 5 Bs and 8 As\r \n" ); document.write( "\n" ); document.write( "so the nth term has (n + 1) Bs and 2n As\r \n" ); document.write( "\n" ); document.write( "to find the term which has exactly 35% Bs: \n" ); document.write( "(n + 1) = 35/100 * (2n + (n + 1)) \n" ); document.write( "<=> n + 1 = 0.35*(3n + 1) \n" ); document.write( "<=> n + 1 = 1.05n + 0.35 \n" ); document.write( "<=> n - 1.05n = 0.35 - 1 \n" ); document.write( "<=> -0.05n = -0.65 \n" ); document.write( "<=> n = 0.65/0.05 = 13\r \n" ); document.write( "\n" ); document.write( "so the 13th term has exactly 35% Bs \n" ); document.write( " \n" ); document.write( " |