document.write( "Question 164033: The first four terms of a pattern are shown below: \r
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document.write( "ABBA
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document.write( "AABBBAA
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document.write( "AAABBBBAAA
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document.write( "AAAABBBBBAAAA \r
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document.write( "Suppose that this pattern continues, with the As and Bs increasing as shown. \r
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document.write( "Find an expression for the number of Bs in the nth term of the pattern.\r
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document.write( "Use your expression to determine which term has exactly 35% Bs.
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Algebra.Com's Answer #120875 by oscargut(2103)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "(Please show source) \n" ); document.write( ".................n \n" ); document.write( "ABBA.............1 2 Bs 2 As \n" ); document.write( "AABBBAA..........2 3 Bs 4 As \n" ); document.write( "AAABBBBAAA.......3 4 Bs 6 As \n" ); document.write( "AAAABBBBBAAAA....4 5 Bs 8 As \n" ); document.write( "........\r \n" ); document.write( "\n" ); document.write( "AAA,,,BBB,,,,AAA.n n+1 Bs 2n As\r \n" ); document.write( "\n" ); document.write( "Answer: Number of Bs in the nth term is n+1\r \n" ); document.write( "\n" ); document.write( "we have to find n such that \n" ); document.write( " Bs/Total =0.35 \n" ); document.write( "then\r \n" ); document.write( "\n" ); document.write( "(n+1)/(n+1+2n)=0.35 \n" ); document.write( "n+1=0.35(3n+1)\r \n" ); document.write( "\n" ); document.write( "n-(1.05)n=0.35-1 \n" ); document.write( "-0.05n=-0.65 \n" ); document.write( "n=0.65/0.05=13\r \n" ); document.write( "\n" ); document.write( "Answer: n=13 \n" ); document.write( " \n" ); document.write( " |