document.write( "Question 164036: Find 3 consecutive odd integers such that the product of the first and third integers is 4 less than the square of the second integer.\r
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Algebra.Com's Answer #120874 by alicealc(293) $\"\"$ $\"About$

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Let:
\n" ); document.write( "the first odd integer = x
\n" ); document.write( "the second odd integer = x + 2
\n" ); document.write( "the third odd integer = x + 4\r
\n" ); document.write( "\n" ); document.write( " $\"x%2A%28x+%2B+4%29+=+%28x+%2B+2%29%5E2+-+4\"$
\n" ); document.write( "<=> $\"x%5E2+%2B+4x+=+x%5E2+%2B+4x+%2B+4+-+4\"$
\n" ); document.write( "<=> $\"x%5E2+%2B+4x+-+x%5E2+-+4x+=+4+-+4\"$
\n" ); document.write( "<=> $\"0+=+0\"$ \r
\n" ); document.write( "\n" ); document.write( "from the result above, we can conclude that every 3 consecutive odd integers has such characteristic (the product of the first and third integers is 4 less than the square of the second integer)
\n" ); document.write( " $\"1%2A5+=+3%5E2+-+4\"$
\n" ); document.write( " $\"3%2A7+=+5%5E2+-+4\"$
\n" ); document.write( " $\"5%2A9+=+7%5E2+-+4\"$
\n" ); document.write( "and so on.\r
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