document.write( "Question 23310: Please help
\n" ); document.write( "s(t) = -16t^2 + 32t Graph this function for 0 < or = t which is < or = to 2.
\n" ); document.write( "Also, what is the maximum height reached by the ball.\r
\n" ); document.write( "\n" ); document.write( "Thanks,
\n" ); document.write( "Paul
\n" ); document.write( "

Algebra.Com's Answer #12086 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "
Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation \"ax%5E2%2Bbx%2Bc=0\" (in our case \"-16x%5E2%2B32x%2B0+=+0\") has the following solutons:
\n" ); document.write( "
\n" ); document.write( " \"x%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca\"
\n" ); document.write( "
\n" ); document.write( " For these solutions to exist, the discriminant \"b%5E2-4ac\" should not be a negative number.
\n" ); document.write( "
\n" ); document.write( " First, we need to compute the discriminant \"b%5E2-4ac\": \"b%5E2-4ac=%2832%29%5E2-4%2A-16%2A0=1024\".
\n" ); document.write( "
\n" ); document.write( " Discriminant d=1024 is greater than zero. That means that there are two solutions: \"+x%5B12%5D+=+%28-32%2B-sqrt%28+1024+%29%29%2F2%5Ca\".
\n" ); document.write( "
\n" ); document.write( " \"x%5B1%5D+=+%28-%2832%29%2Bsqrt%28+1024+%29%29%2F2%5C-16+=+0\"
\n" ); document.write( " \"x%5B2%5D+=+%28-%2832%29-sqrt%28+1024+%29%29%2F2%5C-16+=+2\"
\n" ); document.write( "
\n" ); document.write( " Quadratic expression \"-16x%5E2%2B32x%2B0\" can be factored:
\n" ); document.write( " \"-16x%5E2%2B32x%2B0+=+-16%28x-0%29%2A%28x-2%29\"
\n" ); document.write( " Again, the answer is: 0, 2.\n" ); document.write( "Here's your graph:
\n" ); document.write( "\"graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+-16%2Ax%5E2%2B32%2Ax%2B0+%29\"

\n" ); document.write( "\n" ); document.write( "a=-16, b=32, c=0
\n" ); document.write( "The max or min is found at t=-b/2a = 32/32=1
\n" ); document.write( "Get the correspond \"s\" value by plugging
\n" ); document.write( "in t=1.\r
\n" ); document.write( "\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
\n" ); document.write( "
\n" ); document.write( "
\n" );