document.write( "Question 23297: `SUPPOSE YOU THROW A BASEBALL STRAIGHT UP AT A VELOCITY OF 64 FEET PER SECOND.
\n" ); document.write( "A FUNCTION
\n" ); document.write( "CAN BE CREATED BY EXPRESSING DISTANCE ABOVE GROUND, S, AS A FUNCTION OF TIME, T.
\n" ); document.write( "THIS FUNCTION IS: S=-16T^2+^V0^T+^S0\r
\n" ); document.write( "\n" ); document.write( "16 REPRESENTS 1/2G, THE GRAVITATIONAL PULL DUE TO GRAVITY (MEASURED IN FEET PER
\n" ); document.write( "SECOND^2).
\n" ); document.write( "^V0 IS THE INITIAL VELOCITY (HOW HARD DO YOU THROW THE OBJECT, MEASURED IN FEET
\n" ); document.write( "PER SECOND).
\n" ); document.write( "^S0 IS THE INITIAL DISTANCE ABOVE GROUND (IN FEET). IF YOU ARE STANDING ON THE
\n" ); document.write( "GROUND, THEN ^S0=0.\r
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\n" ); document.write( "\n" ); document.write( "How long will it take to hit the ground?
\n" ); document.write( "What is the maximum height of the ball? Waht time was the maximum height attained?
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Algebra.Com's Answer #12085 by Earlsdon(6294)\"\" \"About 
You can put this solution on YOUR website!
The equation is:
\n" ); document.write( "\"s%28t%29+=+-16t%5E2+%2B+64t\" To find the time (t) at which the ball returns to the ground (s=0), set the above equation equalto 0 and solve for t.
\n" ); document.write( "\"0+=+-16t%5E2%2B64t\" Factor out a t.
\n" ); document.write( "\"0+=+t%28-16t%2B64%29\" Apply the zero product principle.
\n" ); document.write( "\"t+=+0\" and/or \"-64t%2B64+=+0\"
\n" ); document.write( "The solution t=0 would be the situation at the start of this operation. So we are left with:
\n" ); document.write( "\"-16t%2B64+=+0\" Add 64t to both sides of the equation.
\n" ); document.write( "\"64+=+16t\" Divide both sides by 16.
\n" ); document.write( "\"t+=+4\"\r
\n" ); document.write( "\n" ); document.write( "The ball returns to the ground at t = 4 seconds.\r
\n" ); document.write( "\n" ); document.write( "To find the maximum height reached by the ball you first will find the time, t, at which the function s(t) is a maximum. Recall that the quadratic function represents a parabola and the maximum (or minimum) point on a parabola occurs at its vertex. The vertex, in this case, will be a maximum value because the parabola opens downward. How do you know this?...the coefficient of t^2 is negative.\r
\n" ); document.write( "\n" ); document.write( "The x-coordinate (or, in this case, the t-coordinate) of the vertex is given by:\"t+=+-b%2F2a\" where a=-16 and b=64. This is taken from the standard form for the quadratic equation: \"at%5E2%2Bbt%2Bc=0\"\r
\n" ); document.write( "\n" ); document.write( "The t-coordinate of the vertex is:
\n" ); document.write( "\"t+=+%28-64%29%2F2%28-16%29\"
\n" ); document.write( "\"t+=+%28-64%29%2F%28-32%29\"
\n" ); document.write( "\"t+=+2\" The maximum height occurs at time t=2 seconds. Find the maximum height by substituting this value of t into the original function: \"s%28t%29+=+-16t%5E2%2B64t\"\r
\n" ); document.write( "\n" ); document.write( "\"s%282%29+=+-16%282%29%5E2+%2B+64%282%29\"
\n" ); document.write( "\"s%282%29+=+-64%2B128\"
\n" ); document.write( "\"s%282%29+=+64\"\r
\n" ); document.write( "\n" ); document.write( "The maximum height attained by the ball is 64 feet at 2 seconds.
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