document.write( "Question 164010: Solve for F: C=5/9(F-32)
\n" ); document.write( "please explain process thanks
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Algebra.Com's Answer #120841 by orca(409)\"\" \"About 
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\"C=%285%2F9%29%28F-32%29\"
\n" ); document.write( "\"9C=9%2A%285%2F9%29%28F-32%29\" (multiply both sides by 9 to clear the denominator)
\n" ); document.write( "\"9C=5%28F-32%29\"
\n" ); document.write( "\"9C%2F5=5%28F-32%29%2F5\" (divide both side by 5)
\n" ); document.write( "\"%289%2F5%29C=F-32\"
\n" ); document.write( "\"%289%2F5%29C%2B32=F-32%2B32\" (add 32 to both sides)
\n" ); document.write( "\"%289%2F5%29C%2B32=F\"
\n" ); document.write( "So
\n" ); document.write( "\"F=%289%2F5%29C%2B32\"
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