document.write( "Question 163973: Mary needs to go to Jane’s house. Mary drives 4mph going uphill, goes 6mph on flat ground and goes 12mph downhill. It takes her 1 hour to do the trip. How far is Jane’s house? \n" ); document.write( "
Algebra.Com's Answer #120829 by ankor@dixie-net.com(22740)\"\" \"About 
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Mary needs to go to Jane’s house. Mary drives 4 mph going uphill, goes 6 mph
\n" ); document.write( "on flat ground and goes 12 mph downhill. It takes her 1 hour to do the trip.
\n" ); document.write( " How far is Jane’s house?
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\n" ); document.write( "Let d = distance to house
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\n" ); document.write( "Divide the distance into 4 + 6 + 12 = 22 units
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\n" ); document.write( "The distance at each speed:
\n" ); document.write( "\"4%2F22\" = .182d; distance at 4 mph
\n" ); document.write( "\"6%2F22\" = .273d; distance at 6 mph
\n" ); document.write( "\"12%2F22\" = .545d; distance at 12 mph
\n" ); document.write( ":
\n" ); document.write( "Write a time equation, Time = dist/speed
\n" ); document.write( "\"%28.182d%29%2F4\" + \"%28.273d%29%2F6\" + \"%28.545d%29%2F12\" = 1
\n" ); document.write( "Clear the denominator multiply equation 12
\n" ); document.write( "3(.182d) + 2(.273d) + .545d = 12
\n" ); document.write( ":
\n" ); document.write( ".546d + .546d + .545d = 12
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\n" ); document.write( "1.64d = 12
\n" ); document.write( "d = \"12%2F1.64\"
\n" ); document.write( "d = 7.3 miles
\n" ); document.write( ":
\n" ); document.write( "Interesting that this is the same distance if you just averaged the 3 speeds
\n" ); document.write( "\"22%2F3\" = 7.33 mi; in 1 hr, the distance would 7.33 mi
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