document.write( "Question 163985: I'm having a little trouble solving this one.
\n" ); document.write( "Given \"f%28x%29=-sqrt%28x%2B2%29%2B3\", Determine the domain of the inverse \"f%5E-1%28x%29\"I am getting \"-x%5E2%2B6x-11\" as the inverse. So the range would be \"x%3E=-2\"
\n" ); document.write( "Am I on the right track here?
\n" ); document.write( "Thanks for you help.
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Algebra.Com's Answer #120828 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
\"f%28x%29=-sqrt%28x%2B2%29%2B3\" Start with the given function\r
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\n" ); document.write( "\n" ); document.write( "\"y=-sqrt%28x%2B2%29%2B3\" Replace f(x) with y\r
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\n" ); document.write( "\n" ); document.write( "\"x=-sqrt%28y%2B2%29%2B3\" Switch x and y\r
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\n" ); document.write( "\n" ); document.write( "The goal is now to solve for y:\r
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\n" ); document.write( "\n" ); document.write( "\"x-3=-sqrt%28y%2B2%29\" Subtract 3 from both sides\r
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\n" ); document.write( "\n" ); document.write( "\"%28x-3%29%5E2=y%2B2\" Square both sides\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2-6x%2B9=y%2B2\" FOIL the left side\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2-6x%2B7=y%2B2\" FOIL the left side\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2-6x%2B7=y\" Combine like terms.\r
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\n" ); document.write( "\n" ); document.write( "So the solution is \"y=x%5E2-6x%2B7\" which means that the inverse function is \"f%5E-1%28x%29=x%5E2-6x%2B7\" where the domain of \"f%5E-1%28x%29\" is \"x%3C=3\" and the range is \"y%3E=-2\"
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