document.write( "Question 163953This question is from textbook College Algebra
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document.write( ": A cell phone company charges a monthly fee of $10 for the first 1000 text messages and 10 cents for each additional text message. Miriam's bill for text messages for the month of June is $38.50. How many text messages did she send that month?
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document.write( "I can figure out the answer(1285 messages) but I don't know how to write the formula.
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document.write( "Thanks \n" );
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Algebra.Com's Answer #120802 by gonzo(654)![]() ![]() ![]() You can put this solution on YOUR website! total messages for the month is 3850 as follows: \n" ); document.write( "----- \n" ); document.write( "let C = cost \n" ); document.write( "let M = number of messages greater than 1000 \n" ); document.write( "formula is: \n" ); document.write( "C = $10 + $.01*M \n" ); document.write( "----- \n" ); document.write( "substitute known values in equation. \n" ); document.write( "$38.50 = $10 + $.01*M \n" ); document.write( "subtract $10 from both sides of equation. \n" ); document.write( "$28.5 = $.01*M \n" ); document.write( "divide both sides of the equation by $.01. \n" ); document.write( "2850 = M \n" ); document.write( "----- \n" ); document.write( "looks like number of messages greater than 1000 is 2850. \n" ); document.write( "to prove, substitute in original equation. \n" ); document.write( "----- \n" ); document.write( "$38.50 = $10.00 + $.01*2850 \n" ); document.write( "$38.50 = $10.00 + $28.50 \n" ); document.write( "$38.50 = $38.50 \n" ); document.write( "----- \n" ); document.write( "the value of 2850 for M is good. \n" ); document.write( "total messages for the month would be 2850 + 1000 = 3850. \n" ); document.write( "----- \n" ); document.write( " |