document.write( "Question 163953This question is from textbook College Algebra
\n" ); document.write( ": A cell phone company charges a monthly fee of $10 for the first 1000 text messages and 10 cents for each additional text message. Miriam's bill for text messages for the month of June is $38.50. How many text messages did she send that month?
\n" ); document.write( "I can figure out the answer(1285 messages) but I don't know how to write the formula.
\n" ); document.write( "Thanks
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Algebra.Com's Answer #120802 by gonzo(654)\"\" \"About 
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total messages for the month is 3850 as follows:
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\n" ); document.write( "let C = cost
\n" ); document.write( "let M = number of messages greater than 1000
\n" ); document.write( "formula is:
\n" ); document.write( "C = $10 + $.01*M
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\n" ); document.write( "substitute known values in equation.
\n" ); document.write( "$38.50 = $10 + $.01*M
\n" ); document.write( "subtract $10 from both sides of equation.
\n" ); document.write( "$28.5 = $.01*M
\n" ); document.write( "divide both sides of the equation by $.01.
\n" ); document.write( "2850 = M
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\n" ); document.write( "looks like number of messages greater than 1000 is 2850.
\n" ); document.write( "to prove, substitute in original equation.
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\n" ); document.write( "$38.50 = $10.00 + $.01*2850
\n" ); document.write( "$38.50 = $10.00 + $28.50
\n" ); document.write( "$38.50 = $38.50
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\n" ); document.write( "the value of 2850 for M is good.
\n" ); document.write( "total messages for the month would be 2850 + 1000 = 3850.
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