document.write( "Question 163903This question is from textbook Elementary and Intermediate
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document.write( ": 52.) Simplify each complex fraction. Reduce\r
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document.write( "1/9+1/3x
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document.write( "x/9-1/x this problem has a line between the two which make it one problem.
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Algebra.Com's Answer #120800 by ptaylor(2198)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "(1/9 + 1/3x)/(x/9-1/x) \n" ); document.write( "Numerator: (1/9+1/3x); multiply each term by 9x/9x and we get: \n" ); document.write( "((x+3)/9x) \n" ); document.write( "Now denominator: (x/9-1/x); multiply each term by 9x/9x and we get \n" ); document.write( "(x^2-9)/9x but (x^2-9)=(x+3)(x-3) so we have: (x+3)(x-3)/9x\r \n" ); document.write( "\n" ); document.write( "Next put the numerator and denominator back together and we get: \n" ); document.write( "((x+3)/9x)/((x+3)(x-3))/9x Now we can simplify this complex fraction by making the denominator equal to 1. We can do this by multiplying both the numerator and denominator by 9x/((x+3)(x-3)). When we do this, we get: \n" ); document.write( "((x+3)/9x)*(9x/((x+3)(x-3)))/(((x+3)(x-3))/9x)*(9x/((x+3)(x-3))); simplifying, we have: \n" ); document.write( "1/(x-3)/1 or 1/(x-3)---------------------answer\r \n" ); document.write( "\n" ); document.write( "Now lets look at the general form of a complex fraction: \n" ); document.write( "(a/b)/(c/d) Lets make the denominator, (c/d), equal to 1. We can if we multiply the numerator and denominator by (d/c) and we get:\r \n" ); document.write( "\n" ); document.write( "(a/b)(d/c)/(c/d)(d/c) which equals \n" ); document.write( "(ad)/(bc)/1=(ad)/(bc)\r \n" ); document.write( "\n" ); document.write( "After we simplify your problem a little, we can say that: \n" ); document.write( "a=(x+3) \n" ); document.write( "b=9x \n" ); document.write( "c=(x+3)(x-3) and \n" ); document.write( "d=b=9x \n" ); document.write( "So the answer is:(ad)/(bc) or (x+3)*9x/(9x*(x+3)(x-3)) cancel like terms \n" ); document.write( "The 9x's cancel and the (x+3)'s cancel leaving 1/(x-3) \n" ); document.write( "Hope this helps----ptaylor \n" ); document.write( " \n" ); document.write( " |