document.write( "Question 163951This question is from textbook College Algebra
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document.write( ": A rental company charges $65 a day and 30 cents a mile for renting a truck. Michael rents a truck for 3 days, and his bill comes to $275. How many miles did he drive?
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document.write( "I can figure out that the answer is 400 miles, but I don't know how to put it in an algebraic equation form.
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document.write( "Thanks \n" );
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Algebra.Com's Answer #120799 by Edwin McCravy(20055)![]() ![]() You can put this solution on YOUR website! A rental company charges $65 a day and 30 cents a mile for renting a truck. Michael rents a truck for 3 days, and his bill comes to $275. How many miles did he drive? \n" ); document.write( "I can figure out that the answer is 400 miles, but I don't know how to put it in an algebraic equation form. \n" ); document.write( " \r\n" ); document.write( "400 miles cannot be correct, for 30 cents times \r\n" ); document.write( "400 miles gives $120. And $65 times 3 days gives $195. \r\n" ); document.write( "\r\n" ); document.write( "But adding $195 + $120 gives $315, not $275.\r\n" ); document.write( "\r\n" ); document.write( "----------------------\r\n" ); document.write( "\r\n" ); document.write( "Just think how the total bill was figured. It was this way:\r\n" ); document.write( "\r\n" ); document.write( "1. $65 TIMES THE NUMBER OF DAYS \r\n" ); document.write( "\r\n" ); document.write( "PLUS \r\n" ); document.write( "\r\n" ); document.write( "2. $0.30 TIMES THE NUMBER OF MILES\r\n" ); document.write( "\r\n" ); document.write( "EQUALS\r\n" ); document.write( "\r\n" ); document.write( "3. THE TOTAL BILL \r\n" ); document.write( "\r\n" ); document.write( "---------------------\r\n" ); document.write( "\r\n" ); document.write( "Let's look at 1. That's $65 times 3 days or $195.\r\n" ); document.write( "\r\n" ); document.write( "Let's look at 2. We don't know the number of miles, so we let\r\n" ); document.write( "the letter x represent this unknown number. But we can\r\n" ); document.write( "multiply $.30 by x anyway and get $.30x\r\n" ); document.write( "\r\n" ); document.write( "Let's look at 3. That's given as $275.\r\n" ); document.write( "\r\n" ); document.write( "So we have\r\n" ); document.write( "\r\n" ); document.write( "$195 PLUS $.30x EQUALS $275\r\n" ); document.write( "\r\n" ); document.write( "or dropping the dollar signs, and using + for PLUS and = \r\n" ); document.write( "for EQUALS:\r\n" ); document.write( "\r\n" ); document.write( "195 + .30x = 275\r\n" ); document.write( "\r\n" ); document.write( "Now we subtract 195 from both sides:\r\n" ); document.write( "\r\n" ); document.write( " .30x = 80\r\n" ); document.write( "\r\n" ); document.write( "Now we divide both sides by .30\r\n" ); document.write( "\r\n" ); document.write( "\n" ); document.write( " |