document.write( "Question 163904This question is from textbook Elementary and Intermediate
\n" ); document.write( ": Preform the indicated operation. Reduce\r
\n" ); document.write( "\n" ); document.write( "56.) 3/x+1+2/x-1
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Algebra.Com's Answer #120791 by midwood_trail(310)\"\" \"About 
You can put this solution on YOUR website!
We have the following fractions:\r
\n" ); document.write( "\n" ); document.write( "3/(x + 1) + 2/(x - 1)\r
\n" ); document.write( "\n" ); document.write( "Do you recall how to add fraction with different denominators?\r
\n" ); document.write( "\n" ); document.write( "For example, if you have 2/3 + 4/5, what is the answer?\r
\n" ); document.write( "\n" ); document.write( "You can use the same method for adding regular fractions like 2/3 + 4/5 when adding the two given algebraic fractions.\r
\n" ); document.write( "\n" ); document.write( "OUR LCD = (x + 1)(x - 1)\r
\n" ); document.write( "\n" ); document.write( "We divide the LCD by each denominator and then we multiply the quotient by each numerator to find the sum.\r
\n" ); document.write( "\n" ); document.write( "Can you take it from here?\r
\n" ); document.write( "\n" ); document.write( "If not, write back and I will answer the question in full after work.\r
\n" ); document.write( "\n" ); document.write( "Your reply:\r
\n" ); document.write( "\n" ); document.write( "\"I am not sure if I can answer this right or not!\"\r
\n" ); document.write( "\n" ); document.write( "MY REPLY:\r
\n" ); document.write( "\n" ); document.write( "3/(x + 1) + 2/(x - 1)\r
\n" ); document.write( "\n" ); document.write( "Our LCD is (x+1)(x-1)\r
\n" ); document.write( "\n" ); document.write( "3/(x + 1) times (x+1)(x-1)= 3(x - 1) = 3x - 3\r
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\n" ); document.write( "\n" ); document.write( "2/(x -1) times (x+1)(x-1)= 2(x + 1) = 2x + 1\r
\n" ); document.write( "\n" ); document.write( "We now have this fraction over our LCD:\r
\n" ); document.write( "\n" ); document.write( "[3x - 3 + 2x + 1]/(x + 1)(x - 1)\r
\n" ); document.write( "\n" ); document.write( "We combine like terms in the numerator and that's it.\r
\n" ); document.write( "\n" ); document.write( "Final answer: (5x - 2)/(x + 1)(x - 1)\r
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