document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=23307>Question 23307</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Ok this is different to me, the question is<BR>\n" );
document.write( "in the formula of : 2/f+t=3/m,\r<BR>\n" );
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document.write( "it says solve the equation for f(part 1 of the problem),<BR>\n" );
document.write( "then, calculate f from that formauls when<BR>\n" );
document.write( "m=4, and t=3(part 2 of the problem). <BR>\n" );
document.write( "PLease help<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #12077 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=12077\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Multiply thru by \"fm\" to get rid of the fractions:<BR>\n" );
document.write( "2m +ftm =3f<BR>\n" );
document.write( "ftm=3f-2m<BR>\n" );
document.write( "f = (3f-2m)/tm<BR>\n" );
document.write( "If m=4 and t=3 the f=(3(3)-2(4))/((3)(4)<BR>\n" );
document.write( " f= 1/12\r<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.  </SPAN>\n" );
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