document.write( "Question 163882: We have the answer to this problem, but we are unsure of how it was solved. Obviously we got a different answer….please help!\r
\n" ); document.write( "\n" ); document.write( "xº + 2x¹ if x=20
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Algebra.Com's Answer #120723 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
\"x%5E0%2B2x%5E1\" Start with the given expression\r
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\n" ); document.write( "\n" ); document.write( "\"%2820%29%5E0%2B2%2820%29%5E1\" Plug in x=20\r
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\n" ); document.write( "\n" ); document.write( "\"1%2B2%2820%29%5E1\" Raise 20 to the zeroth power to get 1. Note: any number (except zero) to the zeroth power is ALWAYS equal to 1. In other words, \"x%5E0=1\" where \"x%3C%3E0\"\r
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\n" ); document.write( "\n" ); document.write( "\"1%2B2%2820%29\" Raise 20 to the first power to get 20. Note: \"x%5E1=x\" for all x\r
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\n" ); document.write( "\n" ); document.write( "\"1%2B40\" Multiply\r
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\n" ); document.write( "\n" ); document.write( "\"41\" Add\r
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\n" ); document.write( "\n" ); document.write( "So \"x%5E0%2B2x%5E1=41\" when x=20
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