document.write( "Question 163722: How many onces of 5% Hydrochloric acid, 20% hydro. acid, and water must be combined to get 10 oz of solution that is 8.5% hydro. acid if the amount of water used must equal the total amount of the other two solutions? \n" ); document.write( "
Algebra.Com's Answer #120718 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! How many ounces of 5% Hydro-chloric acid, 20% hydro acid, and water must be \n" ); document.write( " combined to get 10 oz of solution that is 8.5% hydro acid if the amount of \n" ); document.write( " water used must equal the total amount of the other two solutions? \n" ); document.write( ": \n" ); document.write( "That means that half the final solution has to be water: 5 oz \n" ); document.write( "And half has to be a mixture of the two acids. \n" ); document.write( "When the two are combined the percent will be halved \n" ); document.write( "Calculate the amt required to make 5 oz of 17% solution \n" ); document.write( ": \n" ); document.write( "Let x = amt of 5% acid \n" ); document.write( "then \n" ); document.write( "(5-x) = amt of 20% acid \n" ); document.write( ": \n" ); document.write( "The equation: \n" ); document.write( ".05x + .2(5-x) = .17(5) \n" ); document.write( ".05x + 1 - .2x = .85 \n" ); document.write( ".05x - .20x = .85 - 1 \n" ); document.write( "-.15x = -.15 \n" ); document.write( ": \n" ); document.write( "x = 1 oz of 5% solution \n" ); document.write( "then \n" ); document.write( "4 - 1 = 4 oz of 20% solution \n" ); document.write( ": \n" ); document.write( "When the 5 oz mixture is mixed with 5 oz of water: \n" ); document.write( ".17(5) = .085(5 + 5) \n" ); document.write( ".85 = .085(10) \n" ); document.write( ".85 = .85 \n" ); document.write( " \n" ); document.write( " |