document.write( "Question 163826: The width of a certain rectangle exceeds twice its length by three inches, and four times its lenght is twelve less than its perimeter. Find the dimensions of the rectangle.\r
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document.write( "this is what i have so far, but am stuck.
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document.write( "P=2L+2W
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document.write( "W=2L+3
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document.write( "P=2L+2(2L+3) \n" );
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Algebra.Com's Answer #120686 by Fombitz(32388)![]() ![]() You can put this solution on YOUR website! You're getting there but you only used half of the information. \n" ); document.write( "\"four times its lenght is twelve less than its perimeter\" \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Now you have another equation for P. \n" ); document.write( "Put that together with your other equation for P. \n" ); document.write( " \n" ); document.write( "Equate them and solve for L. \n" ); document.write( " \n" ); document.write( "Re-post a question if you get stuck. \n" ); document.write( " |