document.write( "Question 163801: judd and judy can clean their apratment together in 3 hours. they each work at the same speed. How long would it take judy to clean it by herself? \n" ); document.write( "

Algebra.Com's Answer #120676 by vleith(2983) $\"\"$ $\"About$

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Given they both work at the same speed, then you know each of them did half the job in 3 hours.\r
\n" ); document.write( "\n" ); document.write( "So it will take each of them twice that to do the job alone. Answer 6 hours\r
\n" ); document.write( "\n" ); document.write( "Algebraically:
\n" ); document.write( "Let the Judd's rate = j and judy's rate = J
\n" ); document.write( "Given
\n" ); document.write( " $\"J+=j+\"$ they go the same rate
\n" ); document.write( " $\"%28J+%2Bj%29+%2A+3+=+Fulljob\"$ both working together take 3 hours to do the whole thing
\n" ); document.write( " $\"j+%2Bj+=+Fulljob%2F3\"$ sub in judy's rate for Judd's using the first equation
\n" ); document.write( " $\"2j+=+Fulljob%2F3\"$
\n" ); document.write( " $\"j+=+FullJob%2F6\"$ so they are each able to do 1/6 of the job an hour.
\n" ); document.write( "How long do to the full job?
\n" ); document.write( "They'll need six hours each.\r
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